Question: Solve the given problems.
According to Newton's law of cooling (Isaac Newton, again), the rate at which a body cools is proportional to the difference in temperature between it and the surrounding medium. By use of this law, the temperature T(in °F) of an engine coolant as a function of the time t(in min) T = 80 + 120(05.5)0.200t is The coolant was initially at 200°F and the air temperature was 80°F Linearize this function for t = 5.00 min and display the graph of T = f(t) and L(t) on a calculator.