A voltaic cell consists of an mnmn2 half-cell and a pbpb2
A voltaic cell consists of an Mn/Mn2+ half-cell and a Pb/Pb2+ half-cell. Calculate [Pb2+] when Ecell is 1.017 V and [Mn2+] = 0.589 M. Use reduction potential values of Mn2+ = -1.18 V and for Pb2+ = -0.13 V.
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a voltaic cell consists of an mnmn2 half-cell and a pbpb2 half-cell calculate pb2 when ecell is 1017 v and mn2 0589 m
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