A voltaic cell consists of a strip of lead metal in a solution of Pb(NO3)2 in one beaker, and in the other beaker a platinum electrode immersed in an NaCl solution, with Cl2 gas bubbled around the electrode. The two beakers are connected with a salt bridge.
(I) Which metal is at the anode?
(II) Which electrode loses mass?
(III) What is the cell potential under standard conditions?
Pb2+(aq) + 2e- <=> Pb(s) Eºred = -0.126 V
Cl2(g) + 2e- <=> 2Cl-(aq) Eºred = +1.359 V
A. (I) Pb, (II) Pt, (III) +1.233V
B. (I) Pt, (II) Pt, (III) -1.485 V
C. (I) Pt, (II) Pb, (III) -1.233 V
D. (I) Pb, (II) Pb, (III) +1.485 V
E. None of the above