A uniform rod of length 0940 m and mass 110 kg is balanced


A uniform rod of length 0.940 m and mass 11.0 kg is balanced on a sharp edge at 0.670 m from the left end. At the left end hangs a mass of 50.0 kg and the right end hangs an unknown mass so that the whole assembly is in equilibrium. Calculate the torque on the center of mass of the rod alone with respect to the pivot point.(in N*m)? Calculate the unknown mass.(in kg)?

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Physics: A uniform rod of length 0940 m and mass 110 kg is balanced
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