Problem- Hydrogen sulfide undergoes successive dissociations to give the sulfide ion, S^(2-). The equilibrium constant for the overall process is K= 1E-20 = [H+]^2 [S2-]/([H_2 S]) A saturated solution of hydrogen sulfide is about 0.1 M and this value is not affected by changes in pH. (a) What is the [S^(2-)] for a solution saturated with hydrogen sulfide at pH=3.-? (b) What is the [S^(2-)] for a solution saturated with hydroge sulfide at pH=11.0?
I have read my textbook moreover I still don't understand so please provide me a very condensed, simple to know answer?