Solve the all given parts of following problem:
Problem: A red ball is thrown down with an initial speed of 1.5 m/s from a height of 25 meters above the ground. Then, 0.4 seconds after the red ball is thrown, a blue ball is thrown upward with an initial speed of 23.4 m/s, from a height of 0.8 meters above the ground. The force of gravity due to the earth results in the balls each has a constant downward acceleration of 9.81 m/s2.
Part I: What is the speed of the red ball right before it hits the ground in m/s?
Part II: How long does it take the red ball to reach the ground?
Part III: What is the maximum height the blue ball reaches?
Part IV: What is the height of the blue ball 1.8 s after the red ball is thrown?
Part V: How long after the red ball is thrown are the two balls in the air at the same height?
I just want the right answer, Thanks!