A proton with a speed of 30x105 ms falls though a potential
A proton with a speed of 3.0x10^5 m/s falls though a potential difference V and thereby increases its speed to 9.0x10^5 m/s. Through what potential difference did the proton fall?
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a proton with a speed of 30x105 ms falls though a potential difference v and thereby increases its speed to 90x105 ms
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