A proton moving freely in a circular path perpendicular to, Physics

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A proton moving freely in a circular path perpendicular to

Solve the following question given below:

Question: A proton moving freely in a circular path perpendicular to a constant magnetic field takes 0.80 µs to complete one revolution.

Part A- Determine the magnitude of the magnetic field.

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Physics: A proton moving freely in a circular path perpendicular to

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Physics: A proton moving freely in a circular path perpendicular to

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