A particle moves along the x axis it is initially at the

Question

Solve the all parts of following question:

Question: A particle moves along the x axis. It is initially at the position 0.160 m, moving with velocity 0.240 m/s and acceleration -0.380 m/s². Suppose it moves with constant acceleration for 3.80 s.

Part A: Find the position of the particle after this time?

= m

Part B: Find its velocity at the end of this time interval.

= m/s

Next, assume it moves with simple harmonic motion for 3.80 s and x = 0 is its equilibrium position. (Assume that the velocity and acceleration is the same as in parts (a) and (b).)

Part C: Find its position.

= m

Part D: Find its velocity at the end of this time interval.

= m/s

Please explain how you came to your conclusion.