A parallel-plate capacitor has plates of area 326times104


Compute each part of given problem:

Problem: A parallel-plate capacitor has plates of area 3.26×104 m2.

Part A: What plate separation is required if the capacitance is to be 1560pF? Assume that the space between the plates is filled with air?

Part B: What plate separation is required if the capacitance is to be 1560pF? Assume that the space between the plates is filled with paper.

I don't just need an answer, work and explanations/walkthrough would be much appreciated! Thank you.

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Physics: A parallel-plate capacitor has plates of area 326times104
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