Question: A moving particle encounters an external electric field that decreases its kinetic energy from 9460 eV to 6990 eV as the particle moves from position A to position B. The electric potential at A is -67.0 V, and that at B is +28.0 V.
Part A: Determine the charge of the particle.
I need help to help to solve the above question and include the algebraic sign (+ or -) with your answer.