Question 1: Determine the maximum depth in a 5-m wide rectangular channel if the flow is to be supercritical with a flow rate of Q = 40 m3/s. What is the critical slope corresponding to the above flow rate? (n = 0.011)
Question 2: A flow of 28 m3s-1 occurs in an earth-lined canal having a base width of 3 m, side slopes of 1(vertical) to 2 (horizontal) and the Manning’s n value of 0.022. Calculate the critical depth and critical slope.
Question 3:
a. A hydraulic jump occurs in a rectangular open channel. The water depths before and after the jump are 0.6 m and 1.5 m, respectively. Calculate the critical depth.
b. A hydraulic jump occurs in a rectangular channel 3 m wide having a discharge of 9 m3s-1. The approach depth is 0.75 m. What is the downstream depth, and what fraction of the upstream energy is dissipated in the jump?
Question 4: Water enters a very wide rectangular channel (Manning’s n = 0.0149) at a velocity of 12.2 ms-1 and a depth of 0.61 m. An H3 curve forms downstream and the water jumps to a depth of 2.4 m some distance downstream. Find the distance downstream to the location of the hydraulic jump.
Question 5: A long wide rectangular channel carries a steady flow rate of 35 m2s-1 (flow per unit width) and passes through an abrupt change in slope from 0.005 (upstream of the change) to 0.003 (downstream). Manning’s n for the channel is 0.013. Is there a hydraulic jump in the channel and if so where? Describe the water surface profiles at the various parts of the channel.
Question 6: 6. Question from Hydrology section
Note:
(i) The numerical values for the variables in the questions are based on your ID number and you must use the appropriate values for answering the questions. Failure to do so will result in no marks being awarded to those questions.
The following variable is used in the questions: R
If the last two digits of your ID is greater than or equal to 45 then R = the last two digits
If the last two digits of your ID is less than 45, then R = 45 + the last two digits
Example: If the ID =230675467, then R = 67
If the ID = 230675134, then R = 45 + 34 = 79
Note that your R value can only be between 45 and 99 (both inclusive)
6 (b)
Flood peaks of a river for 5-yr and 100-yr return periods are given as (100 + R) and (400 + R) m3/s respectively:
i. Calculate mean (X) and standard deviation ( S ) of the river floods assuming that Gumbel distribution fits the data
ii. Using Normal distribution calculate 50 and 100 year return period flood peaks,
iii. Calculate 50 and 100 year return period flood peaks using 2-parameter Log-Normal distribution. The mean (Y), standard deviation (Sy ) and skewness coefficient (gy) of the logarithms (base 10) of the annual flood peaks are given as follows:
Y= 2 + R/1000, Sy = 0.4 + R/1000 , gy= -(R /100)
iv. For statistics of the log transformed data in (iii), calculate flood peak for 50 and 100 year return periods using the Log-Pearson
Attachment:- Hydro-Hydraulics.pdf