A hydraulic jack has 2 pistons. The SMALLER piston of area A1=0.2 m^2 has force F1=700N applied to it. The force exerted by the liquid in the jack on the LARGER piston equals F2=6000N. Explain and show equations:
a. What is the increase in pressure inside the jack DUE to force F1?
b. What is the Area of the LARGER piston.