when energy is added to a fluid the temperature of the fluid increases. an equation describing this phenomenon is: Q=M(C_p_)(delta T)
Where: Q is the amount of energy added (joules)
M is the mass of the fluid (kg)
C (subscript p) is the heat capacity of the fluid (joules/kg/K)
Delta T is the change in temperature (K or C degrees)
A garage (24 ft x 24 ft x 10 ft) is illuminated by (6) 60 watt incandescent bulbs. It is estimated that 90% of the energy to an incandescent bulb is dissipated as heat. If the bulbs are left on for 3 hours, how much would the temperature in the garage increase because of the light bulbs (assuming no energy losses). Here is some potentially useful information: Air density (approximate): 1.2 kg/m cubed Air heat capacity (approximate): 1000 joules/kg?K 3.28 ft = 1 m i need to find the Total bulb power in W Total bulb power lost as heat in W Total bulb power lost as heat in joules/second Total bulb power lost as heat in joules Garage air bolume in m^3 garage air mass in kg temperature change in K?