A distance of 7255 ft is recorded using a steel tape


1.Compute the required layout distance if the Temperature is 13 degrees celcius, Tape Length is 29.990 m, and the required Layout distance is 500.000 m.

2.Compute the corrected horizontal distance if Temperature is 100 degrees farenheit, Tape Length is 100.03 ft, Slope is at -0.80%, Slope Measurement is 298.70 ft.

3.A 30-m tape has a mass of 544 g and is supported only at the ends with a force of 80 N. what is the sag correction?.

4.A distance of 72.55 ft is recorded using a steel tape weighing 0.016 lb per foot. The tapes is supported only at the ends with a tension of 15 lb. Find the distance corrected for sag.

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Civil Engineering: A distance of 7255 ft is recorded using a steel tape
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