A certain memory has a capacity of 4K × 8
(i) How many data input and data output lines does it have?
(ii) How many address lines does it have?
(iii) What is its capacity in bytes?
Ans.
(i) available capacity =4Kx8
= 210 x210 x 8
= 212x8
Since in the 4Kx8 ,the second number shows the number of bits in each word therefore the number of data input lines will be 8 and also the data output lines.
(ii) That has total 4K (212) address line that are required to address 212 locations.
(iii) Capacity in bytes of this is 4K bytes.