Question - A 10.00-mL sample of 0.1000 M KH2PO4 was titrated with 0.1000 M HCl Ka for phosphoric acid (H3PO4):
Ka1= 7.50x10-3; Ka2=6.20x10-8; Ka3= 4.20x10-10
Calculate the pH after addition of 10.00 mL of HCl to the KH2PO4 solution?
Please help and explain the steps. I'll reward to the best explanation.
Do I have to do all the steps of the titration up to this point to find it? What can I do with Ka since it isn't pKa?
Please write answer for each section to receive points