A 0.4600 g sample of carboxylic acid is burned in oxygen, producing 0.8202 g of CO2 and 0.3377 g of H20. Determine the empirical formula of the carboxylic acid.
I can't figure out what I am doing wrong. Please help if you can!
Here's what I have:
C: .8202g x (12.01/44g)= .224g
H: .3377g x (1.008g/18g)+.019g
To find oxygen I did: .3377g - (.224g+.019g) = .095g of O
Then I did:
C: 8202g / 12.01 = .068 mol
H: .019g / 1.008= .019 mol
O: .095/16.00= .006 mol