Problem- 50ml of malonic acid, HO2CCH2CO2H is titrated to the second equivalence point by 35.71ml of 0.1750M NaOH. Determine the initial concentration of the malonic acid slution.
HO2CCH2CO2(aq) + H2O<-->H02CCH2COO-(aq) + H30 (aq) Ka1= 1.42x10^-3
H02CCH2COO(aq) +H2O<-->-OOCCH2COO-(aq) + H30 (aq) Ka2= 2.01x10^-6
Explicate the each step. Explicate the process and each step.