28h18l 25o2g gt 16co2g 18h2ol h -11200 kj standard
2C8H18(l) + 25O2(g) => 16CO2(g) + 18H2O(l) ?H = -11,200. kJ Standard enthalpies of formation, ?Hf: CO2(g), -393.5 kJ/mol; H2O(l), -285.8 kJ/mol Use the above data to calculate the standard enthalpy of formation of octane, C8H18(l).
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