2als 6hclaq 2alcl3aq 3h2g according to the equation above


2Al(s) + 6HCl(aq) 2AlCl3(aq) + 3H2(g) According to the equation above, how many grams of aluminum are needed to completely react with 3.93 mol of hydrochloric acid?

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Chemistry: 2als 6hclaq 2alcl3aq 3h2g according to the equation above
Reference No:- TGS0786285

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