281 g of tetraantimony hexoxide reacted with enough carbon


Assignment

1. If 5.26 L of nitrogen monoxide and 7.64 L of oxygen are combined. What mass of nitrogen dioxide will formed? 2NO + O2 → 2NO2

2. 46.1 g of cesium and 13.4 g oxygen reacted-to form 28.3 g of cesium oxide. Which reactant was the limiting reactant? What was the percent yield of this reaction? 4 Cs + O2 → 2 Cs2O

3. 28.1 g of tetraantimony hexoxide reacted with enough carbon to form 17.3 g of antimony. What was the percent yield of this reaction? Sb4O6 + 6C → 4 Sb + 6 CO

4. At STP condition, 10 L nitrogen gas and 15 L hydrogen gas reacted to form 8.5 L ammonia gas. Which reactant was the limiting reactant? And what was the percent yield of this reaction? _ N2 + _H2 →  _ NH3

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Chemistry: 281 g of tetraantimony hexoxide reacted with enough carbon
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