2 Kg of ice at -20 degree C is diverse with 5Kg of water 20 degree C in an insulating vessel having negligible heat capacity. Measure the final mass of water remaining in the container. It is given that the particular heats of water and ice are 1Kcal/kg/degree C and 0.5Kcal/kg/degree C whereas latent heat of fusion of ice is 80 kcal/kg
Ans) apply the formula of mcT and at first measure the amount of heat losed by water at 0 degree.
The calculate the amount of heat gained by ice to go to 0 degree.
Now subtract the second from the first to get heat left for absorption.
Equate this heat to (mL)=latent heat ...and get the mass of new water produced.
You will get it as 1 kg.
Hence the 5+1=6 kg