1abx 1a1b1x ab ne 0ans 1abx
1/a+b+x =1/a+1/b+1/x a+b ≠ 0
Ans: 1/a+b+x =1/a+1/b+1/x
=> 1/a+b+x -1/x = +1/a +1/b
⇒ x - (a + b + x)/x(a + b + x) = + a + b/ ab
⇒(a+b){x(a+b+x)+ab}=0
⇒x(a+b+x)+ab=0
⇒x2 +ax+bx+ab=0
⇒(x+a)(x+b)=0
⇒x=-a x=-b
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