1.00 mole of sodium carbonate (formula mass 106.0) is converted to sodium chloride, Na2CO3(s) + 2HCl(aq)® 2NaCl(aq) + H2O +CO2(g). The percentage yield in this conversion is 80%.Which of the following is correct:
a. 0.80 moles of sodium chloride is produced
b. 1.80 moles of sodium chloride is produced
c. 58.5 x 0.80 grams of sodium chloride is produced
d. 2 x 58.5 x 0.80 grams of sodium chloride is produced