Critical Path in Network Analysis
Basic Scheduling Computations
The notations used are
(i, j) is Activity with tail event i and head event j
Ei is Earliest occurrence time of event i
Lj is Latest allowable occurrence time of event j
Dij is Estimated completion time of activity (i, j)
(Es)ij is Earliest starting time of activity (i, j)
(Ef)ij is Earliest finishing time of activity (i, j)
(Ls)ij is Latest starting time of activity (i, j)
(Lf)ij is Latest finishing time of activity (i, j)
The process is as follows
The calculation commences from the start node and goes towards the end node. For easiness, the forward pass computation begins by assuming the first occurrence time of zero for the first project event.
i. Earliest starting time of activity (i, j) is also the earliest event time of the tail end event, that is (Es)ij = Ei
ii. Earliest finish time of activity (i, j) is also the earliest starting time + the activity time, that is (Ef)ij = (Es)ij + Dij or (Ef)ij = Ei + Dij
iii. Earliest event time for event j is the maximum of the earliest finish times of each and every activities end in to that event, that is Ej = max [(Ef)ij for all immediate predecessor of (i, j)] or Ej =max [Ei + Dij]
For end event suppose E = L. Remember that all E's have been calculated by forward pass computations.
Latest finish time for activity (i, j) is equivalent to the latest event time of event j, that is (Lf)ij = Lj
Latest starting time of activity (i, j) is equal to the latest completion time of (i, j) - the activity time or (Ls)ij =(Lf)ij - Dij or (Ls)ij = Lj - Dij
Latest event time for event 'i' is the least of the latest start time of all activities originating from that event, that is Li = min [(Ls)ij for all immediate successor of (i, j)] = min [(Lf)ij - Dij] = min [Lj - Dij]
There are three types of floats
Mathematically
(Tf)ij = (Latest start - Earliest start) for activity ( i - j)
(Tf)ij = (Ls)ij - (Es)ij or (Tf)ij = (Lj - Dij) - Ei
(Ff)ij = (Earliest time for event j - Earliest time for event i) - Activity time for ( i, j)
(Ff)ij = (Ej - Ei) - Dij
(If)ij = (Ej - Li) - Dij
The negative independent float is always considered as zero.
Head event slack = Lj - Ej, Tail event slack = Li - Ei
solanaceae involves about 90 genera and in excess of 2,800 species. the plants are extensively distributed in tropical and subtropical regions.
www.tutorsglobe.com offers conic section homework help, conic section assignment help, online tutoring assistance, geometry mathematics solutions by online qualified math tutor's help.
Theory and lecture notes of Numerical Differentiation all along with the key concepts of functions and data, Approximating derivatives from data, Errors of approximation, Partial Derivatives. Tutorsglobe offers homework help, assignment help and tutor’s assistance on Numerical Differentiation.
Avail comprehensive support to get rid of assignment problems with Particle Physics Assignment Help tutors.
carbon and its compounds tutorial all along with the key concepts of allotropes of carbon, diamond, graphite, amorphous carbon, properties of carbon, chemical properties of carbon, oxides of carbon and carbon cycle in nature
Cash Flows from Operating Activities, is the net outflow or inflow from trading operations, after tax payments (or receipts) and cash paid to meet financing costs.
www.tutorsglobe.com offers winwin spiral model homework help, assignment help, case study, writing homework help, online tutoring assistance by computer science tutors.
The Analysis of Alum tutorial all along with the key concepts of Melting Temperature test materials, Water of Hydration test materials, Find out the Melting Temperature of Alum, Find out the Water of Hydration of Alum, Find out the Percent sulphate of Alum
tutorsglobe.com amphibious hydrophytes assignment help-homework help by online hydrophytes tutors
tutorsglobe.com price and output determination assignment help-homework help by online monopoly tutors
over the past 25 years, the environment in which businesses operate has become more and more competitive and turbulent.
Theory and lecture notes of Data Description all along with the key concepts of Skewed Distribution, Symmetric Distribution, Midrange, Population Variance, Empirical or Normal Rule, Standard Score or Z-Score and Outlier. Tutorsglobe offers homework help, assignment help and tutor’s assistance on Data Description.
is biophysics assignment driving you insane? avail biophysics assignment help from qualified tutors at viable rates and secure a++!
The statement of cash flows should assist users to assess the capability of a company to produce cash and to assess the need of company for cash.
tutorsglobe.com income effects assignment help-homework help by online comparative statics tutors
1938908
Questions Asked
3689
Tutors
1451421
Questions Answered
Start Excelling in your courses, Ask an Expert and get answers for your homework and assignments!!