Measurement and Density:
Purpose:
Section 1: Through calculating the density of a recognized substance (water), find out the relative precision and precision of different glassware items.
Section 2: Find out the density of a salt water solution using the most precise and correct piece of glassware concluded in section 1
Equipment / materials:
Weighing balance
Water
Unknown metal
cube
100 mL beaker
Unknown liquid
100 mL graduated cylinder
Metal cylinder
Introduction:
The capability to build accurate and featured observations is vital in science. This chapter will focus on quantitative observations, more purposely, measurements. A measurement is described via a number and a scale or unit. The scale utilized is often changed. Due to convenience, the metric system is often utilized in many countries. The universal scale, though, utilized via scientists is the SI unit. In this chapter, we will focus on making accurate and detailed observations in measurements using the metric system while obeying the rules of significant figures.
In calculation to quantities described via a single unit, quantities can as well be described through a combination of units. One such instance is density. Density is simply one way to differentiate a material. Density (d) is described as mass (m) per unit volume (V). Therefore, units of both mass (for example g) and volume (for example mL) are needed in order to find out density.
D = m/V
Instances
1. A cube of copper was originated to contain a mass of 0.630 kg. What are the dimensions of the cube? (The density of copper is 8.94 g/cm3).
Solution:
a) Find out the volume of the cube (note that kg have been converted to g):
8.94 g/cm3
= 630 g / volume
volume = 70.47 cm3
b) Each side of a cube is equivalent in length, so take cube root of the volume for length of cube side:
[cube root of] 70.47 cm3
= 4.13 cm
2. A cube of copper was originated to have a mass of 0.630 kg. What are the dimensions of the cube? (The density of copper is 8.94 g/cm3.)
8.94 g/cm3 = 630 g / volume
[Cube root of] 70.47 cm3 = 4.13 cm.
3. A graduated cylinder is filled to the 40.00 mL mark by mineral oil. The masses of the cylinder previous to and after the computation of mineral oil are 124.966g and 159.446g. In a divide experiment, a metal ball bearing of mass 18.713 g is situated in the cylinder and the cylinder is once more sealed to the 40.00 mL mark by the mineral oil. The joined mass of the ball bearing and mineral oil is 50.952 g. Compute the density of the ball bearing.
a) Determine the density of the mineral oil:
159.446 g minus 124.966 g = 34.480 g
34.480 g / 40.00 mL = 0.8620 g/mL
b) Determine the volume of the ball bearing:
50.952 g minus 18.713 = 32.239 g (this is the mass of mineral oil)
32.239 g divided by 0.8620 g/mL = 37.40 mL (this is the volume of mineral oil)
40.00 mL - 37.40 mL = 2.60 mL
c) The density of the ball bearing is 7.197 g/mL. This came from 18.713 g divided by 2.60 mL.
EXPERIMENT - Measurement and Density
Part A: Density of Liquids
i) Density of Water:
ii) Density of an Unknown Liquid:
Start through another dry graduated cylinder and do again the mass and volume measurements (above steps 1-7) via an unknown liquid (A, B or C assigned by the instructor). Calculate the density of the liquid, identify it (after discussing with the instructor), and compute the % error.
Part B: Density of Solids
i) Density of an unknown metal cylinder:
We will see the level of the water inside the graduated cylinder has risen. Evidence the new volume now (important figures once more). The variation in the volume levels provides us the volume of the metal cylinder
Now compute the density of the metal from volume using 2 different techniques.
ii) Density of an unknown metal cube:
DATA and CALCULATIONS:
Part A: Density of liquids
(i) Density of water:
Temperature of water: _____________
Mass of empty graduated cylinder: _____
Trial 1
Trial 2
Trial 3
Volume of water (mL)
Mass of water +
graduated
cylinder (g)
Mass of water alone (g)
Density of water
(g/mL)
Density from literature
% error
(ii) Density of unknown liquid: _____ (A/B/C)
Temperature of liquid: _____________
Mass of empty graduated cylinder: _________
Volume of liquid(mL)
Mass of liquid+
Mass of liquid alone (g)
Density of liquid
Part B: Density of solids
Density of unknown metal cylinder #: ___
Density from diameter and height measurement:
Mass of
metal
cylinder
(g)
Diameter
(cm)
Height
Volume =
_____(cm3)
Density
of
(g/cm3)
from
literature
%
error
i) Density from volume displacement:
Volume of
water before
dropping metal
cylinder (mL)
Volume of water
after immersing
the metal
(mL)
Density of
ii) Density of unknown metal cube #: ___
Mass
meta
l
Dept
h
Heigh
t (cm)
Widt
_____(cm3
)
Error
Tutorsglobe: A way to secure high grade in your curriculum (Online Tutoring)
Expand your confidence, grow study skills and improve your grades.
Since 2009, Tutorsglobe has proactively helped millions of students to get better grades in school, college or university and score well in competitive tests with live, one-on-one online tutoring.
Using an advanced developed tutoring system providing little or no wait time, the students are connected on-demand with an expert at https://www.tutorsglobe.com. Students work one-on-one, in real-time with a tutor, communicating and studying using a virtual whiteboard technology. Scientific and mathematical notation, symbols, geometric figures, graphing and freehand drawing can be rendered quickly and easily in the advanced whiteboard.
Free to know our price and packages for online chemistry tutoring. Chat with us or submit request at [email protected]
Theory and lecture notes of Aggregate Supply and Phillips Curve all along with the key concepts of aggregate supply, phillips curve, Three Faces of Aggregate Supply, Okun’s law. Tutorsglobe offers homework help, assignment help and tutor’s assistance on Aggregate Supply and Phillips Curve.
tutorsglobe.com immunology assignment help-homework help by online microbiology tutors
www.tutorsglobe.com offers psychology homework help, psychology assignment help, online psychology tutoring assistance, psychology solutions by online qualified and experienced psychology tutor's help.
www.tutorsglobe.com offers acidity of a c–h homework help, acidity of a c–h assignment help, online tutoring assistance, organic chemistry solutions by online qualified tutor's help.
tutorsglobe.com laboratory diagnosis of diphtheria assignment help-homework help by online corynebacterium diphtheria tutors
Polarization of Light tutorial all along with the key concepts of Polarized and Unpolarized Light, Optical Activity, Polarization by Reflection, Polarization by Refraction, Double refraction, birefringence
tutorsglobe.com hyper–inflation assignment help-homework help by online inflation and deflation tutors
1. if rewinding is completed, make use of the presented winding wire gauge number for the new winding.
Instrumental Method Analysis tutorial all along with the key concepts of Classical vs Instrumental Techniques, benefits of instrumental techniques, Electrochemical procedure, mass spectroscopy
Essentials for success of uniform costing system, the success of the uniform costing is relies on Mutual belief and understanding, Accounting policies and principles, Classification and codification, etc.
alkynes tutorial all along with the key concepts of types of alkynes, physical properties, spectral properties, preparation, dehydrohalogenation of dihalides, acidity of alkynes
tutorsglobe.com viruses assignment help-homework help by online biodiversity tutors
tutorsglobe.com structure of antibodies assignment help-homework help by online structure and characteristics of antibodies tutors
linear motion tutorial all along with the key concepts of Motion in a Straight Line and Parameters for describing Motion, Displacement, Velocity, Instantaneous velocity, Average and instantaneous acceleration, Rectilinear motion with constant acceleration, Rectilinear Motion Equations
Avail finest Cognitive Science Assignment Help service today and get authentic and plagiarism free solutions with amazing discounts.
1948611
Questions Asked
3689
Tutors
1443354
Questions Answered
Start Excelling in your courses, Ask an Expert and get answers for your homework and assignments!!