--%>
Assignment Help - homework help

What is Henry law constant and its values?

1. The units of Henry Law constant are same as those of pressure, i.e. torr or h bar.


2. Different gases have dissimilar values of Henry law constant. The values of KH for some gases in water are given in table below:

KH values of some gases in water at 298 K

Gas

kH (k bar)

Gas

kH (k bar)

H2

71.18

CH4

41.85

N2

86.78

CO2

1.67

O2

44.0

HCHO

1.83 × 10-5

Ar

40.3

CH2 = CHCl

0.611


3. The KH values of a gas are different in different solvents and it increases with the increase in temperature. For example the KH values of some gases in different solvents and also at different temperatures are given in table below:

KH values of some gases in different solvents and at different temperatures:

2064_henry law.png 

4. The knowledge of KH value of a gas at given temperature can help us in calculation of its solubility at the temperature. It is important to note that as the temperature is increased the solubility of gas decreases. This implies that higher the value of KH of a gas is, lower will be its solubility and vice versa.

   Related Questions in Chemistry

  • Q : Question related to colligative

    The colligative properties of a solution depend on: (a) Nature of solute particles present in it (b) Nature of solvent used (c) Number of solute particles present in it (d) Number of moles of solvent only

    		•
  • Q : Alkaline medium The amount of KMnO 4

    The amount of KMnO4 required to prepare 100 ml of 0.1N solution in alkaline medium is: (a) 1.58 gm (b) 3.16 gm (c) 0.52 gm (d) 0.31 gmAnswer: (a) In alkaline medium KMnO4 act as ox

    		•
  • Q : Concentration factor affected by

    Can someone please help me in getting through this problem. Which of the given concentration factor is affected by the change in temperature: (1) Molarity (2) Molality (3) Mole fraction (4) Weight fraction

    		•
  • Q : Determining highest normality What is

    What is the correct answer. Which of the given solutions contains highest normality: (i) 8 gm of KOH/litre (ii) N phosphoric acid (iii) 6 gm of NaOH /100 ml (iv) 0.5M H2SO4

    		•
  • Q : Problem based on molality of glucose

    Select the right answer of the question. If 18 gm of glucose (C6H12O6) is present in 1000 gm of an aqueous solution of glucose, it is said to be: (a)1 molal (b)1.1 molal (c)0.5 molal (d)0.1 molal

    		•
  • Q : Explanation of oxygen family. Group 16

    Group 16 of periodic

    		•
  • Q : Thermodynamics 1 Lab Report I already

    I already did Materials and Methods section. I uploaded it with the instructions. Also, make sure to see Concept Questions and Thinking Ahead in the instructions that I uploaded. deadline is tomorow at 8 am here is the link to download all instructions because I couldn't attach all of t

    		•
  • Q : What are condensation polymers? Give

    These types of polymers are formed as a result of condensation reaction between monomer units. Some common examples are being discussed here: 1. Polyesters 2047_condensat</span></p> </div> <!-- /comment-box --> </li> </td> </tr><tr> <td> <li> <div class=

    Q : Define tripod and its use Illustrate a

    Illustrate a tripod? And how it’s used?

    		•
  • Q : Question based on relative lowering of

    Give me answer of this question. When a non-volatile solute is dissolved in a solvent, the relative lowering of vapour pressure is equal to: (a) Mole fraction of solute (b) Mole fraction of solvent (c) Concentration of the solute in grams per litre (d) Concentratio

    		•