--%>

What is heat capacity and how to calculate heat capacity

The temperature reliance of internal energy and enthalpy depends on the heat capacities at constant volume and constant pressure.


The internal energy and enthalpy of chemical systems and the energy changes that accompany chemical reactions depend on the temperature. To make full use of the thermodynamic date we developed, we must see how these data are extended to temperatures other than 25°C.

Heat capacities; it is convenient to deal separately constant pressure processes when the temperature is raised and the energy of the system increases. The heat capacity, already introduced and experimentally determined, as the decrease in the energy of the thermal surroundings that provides the energy to increase the temperature of the system by 1°C, under the specified conditions. Thus we define

1966_heat capacity.png 

And 

68_heat capacity1.png 

If you think of an actual measurement, you see that to increase the temperature of the system, i.e. for ΔT to be positive, there will be a decrease in the energy of the thermal surroundings, that is, ΔUtherm will be negative. The definitions are then being seen to make heat capacities positive quantities.

Heat capacities at constant pressure CP will be used more than will heat capacities at constant volume CV. Some values for CP are given for a temperature of 25°C. All these values for liquids and solids come from experimental, calorimetric studies that depend on the defining equation. Some of the values for gases are experimental, and others are based on calculations of the type of physical properties.

Heat capacities can be used to extend the 25°C thermodynamic quantities to other temperatures. To do so, we will need heat capacity values over a range of temperatures. An analytical expression, rather than a table of values, is needed for most of the calculations we will do. The two empirical CP versus T expressions that have been most used are

CP = a' + b't + c'T2 + ....

And, CP = a + bT + cT-2 + ...

The second of these two forms is more satisfactory. The coefficients that have been deduced for this equation are given for a few substances.

Heat capacities and internal energies and enthalpies: heat capacities, defined in terms of energy changes in the thermal surroundings, can be expressed in terms energy changes in the system.

If any ordinary chemical process occurs and the system has a constant volume ΔUmech = 0 and ΔU = -ΔUtherm, we can express CV as

2156_heat capacity2.png 

If the system is maintained at a constant pressure, ΔH = - ΔUtherm. We can express CP as

190_heat capacity3.png 

Heat capacities in J K-1 mol-1 at constant pressure (parameters for the equation C°P = (a + bT + cT-2):

327_heat capacity4.png 

Heat capacities are characteristics of the system. They are directly linked to the way the internal energy and enthalpy change with temperature when the volume or pressure of the system is correctly controlled.

   Related Questions in Chemistry

  • Q : Explain Rotational Vibrational Spectra

    The infrared spectrum of gas samples shows the effect of rotational-energy changes along with the vibrational energy change.As we know from the interpretations given to thermodynamic properties of gases, gas molecules are simultaneously rotating and vibrating. It follows that an absor

  • Q : Amines arrange in order of

    arrange in order of basicity,pyridine,pipyridineand pyorine

  • Q : Raoults law Give me answer of this

    Give me answer of this question. Provide solution of this question. Which one of the following is the expression of Raoult's law: (a) P-P1/P = n/n+N (b) P1-P/P = N/ N+n (c)P-P2/P1= N/ N-n (d) P1-P/P2= N-n/N

  • Q : P block bif3 is ionic while other

    bif3 is ionic while other trihalides are covalent in nature

  • Q : Molecular crystals Among the below

    Among the below shown which crystal will be soft and have low melting point: (a) Covalent  (b) Ionic  (c) Metallic  (d) MolecularAnswer: (d) Molecular crystals are soft and have low melting point.

  • Q : Problem on decomposition reaction

    Nitrogen tetroxide (melting point: -11.2°C, normal boiling point 21.15°C) decomposes into nitrogen dioxide according to the following reaction: N2O4(g) ↔ 2 NO2(g)<

  • Q : DNA Organic Explain DNA organic in

    Explain DNA organic in brief?

  • Q : Colligative effect Choose the right

    Choose the right answer from following. Which one of the statements written below concerning properties of solutions, explain a colligative effect: (a) Boiling point of pure water decreases by the addition of ethano (b) Vapour pressure of pure water d

  • Q : What is protein in Chemistry Illustrate

    Illustrate what is protein in Chemistry?

  • Q : Question 6 A student was analyzing an

    A student was analyzing an unknown containing only Group IV cations. When the unknown was treated with 3M (NH4)2CO3 solution, a white precipitate formed. Because the acetic acid bottle was empty, the student used 6M HCl to dissolve the precipitate. Following the procedure of this experiment, the stu