--%>

What are Vander Waal's Radii?

Vander Waal's radii can be assigned to the atoms of molecules on the basis of the closeness of approach of these atoms in crystalline substances. 

Diffraction studies of crystals give information about hoe molecules can approach each other and can pack together. Forces, often treated under the name vander Waal's forces, provide the attraction and repulsion between molecules that are responsible for the closeness with which molecules can approach other. The idea of a vander Waals radius for each covalently bound atom is introduced. The shapes attributed to molecules as a result of the introduction of vander Waals radii.

The values of these radii can be deduced from the distances that separate atoms in different molecules in a crystal lattice. In crystalline Br2, the shortest distance between a bromine atom of one molecule and that of an adjacent molecule is 390 pm. Half this value, 195 pm, can therefore be assigned as the van der Waals radius of a covalently bound bromine atom. In similar ways, by making use of crystal structure data for many organic compounds, the van der Waals radii can be deduced. These values must be considered reliable to not more than about 5 pm, and this uncertainty makes itself evident in the range of values found for a particular element in different compounds and crystals. The values are sufficiently reliable, however, for scale drawings to be constructed and used to see hoe molecules can fit together. That van der Waals radii can be assigned with some success is attributable to the fact, mentioned, that the repulsive forces set in very strongly i.e. the potential energy curve raised very steeply, as atoms approach each other. It follows that even when rather different attractive forces operate, the closeness of approach is affected little.


2125_Vander waals.png

   Related Questions in Chemistry

  • Q : Problem based on lowering in vapour

    Help me to solve this problem. An aqueous solution of glucose was prepared by dissolving 18 g of glucose in 90 g of water. The relative lowering in vapour pressure is: (a) 0.02 (b)1 (c) 20 (d)180

  • Q : Explain Second Order Rate Equations.

    Integration of the second order rate equations also produces convenient expressions for dealing with concentration time results.A reaction is classified as second order if the rate of the reaction is proportional to the square of the concentration of one o

  • Q : Benefits of soapy detergents over the

    What are the benefits of soapy detergents over the soap less detergents? Briefly state the benefits?

  • Q : Vapour pressure of benzene Give me

    Give me answer of this question. The vapour pressure of benzene at a certain temperature is 640mm of Hg. A non-volatile and non-electrolyte solid weighing 2.175g is added to 39.08g of benzene. The vapour pressure of the solution is 600,mm of Hg . What is the mo

  • Q : Question associated to vapour pressure

    Choose the right answer from following. The vapour pressure lowering caused by the addition of 100 g of sucrose(molecular mass = 342) to 1000 g of water if the vapour pressure of pure water at 25degree C is 23.8 mm Hg: (a)1.25 mm Hg (b) 0.125 mm Hg (c) 1.15 mm H

  • Q : Molar and Volumetric flow rate problem

    Cyclohexane (C6H12) is produced by mixing Benzene and hydrogen. A process including a reactor, separator, and recycle stream is used to produce Cyclohexane. The fresh feed contains 260L/min C6H6 with 950 L/min of H2

  • Q : Molecular weight of substance The

    The boiling point of a solution of 0.11 gm of a substance in 15 gm of ether was found to be 0.1oC higher than that of the pure ether. The molecular weight of the substance will be (Kb = 2.16)       (a) 148 &nbs

  • Q : What type of bond does HCl encompass

    What type of bond does HCl encompass? Describe briefly?

  • Q : Calculation of concentration of the

    Choose the right answer from following. 200ml of a solution contains 5.85 dissolved sodium chloride. The concentration of the solution will be(Na= 23: cl = 35.5 ) (a) 1 molar (b) 2 molar (c) 0.5 molar (d) 0.25 molar

  • Q : Molality of glucose Help me to go

    Help me to go through this problem. Molecular weight of glucose is 180. A solution of glucose which contains 18 gms per litre is : (a) 2 molal (b) 1 molal (c) 0.1 molal (d)18 molal