--%>

What are Vander Waal's Radii?

Vander Waal's radii can be assigned to the atoms of molecules on the basis of the closeness of approach of these atoms in crystalline substances. 

Diffraction studies of crystals give information about hoe molecules can approach each other and can pack together. Forces, often treated under the name vander Waal's forces, provide the attraction and repulsion between molecules that are responsible for the closeness with which molecules can approach other. The idea of a vander Waals radius for each covalently bound atom is introduced. The shapes attributed to molecules as a result of the introduction of vander Waals radii.

The values of these radii can be deduced from the distances that separate atoms in different molecules in a crystal lattice. In crystalline Br2, the shortest distance between a bromine atom of one molecule and that of an adjacent molecule is 390 pm. Half this value, 195 pm, can therefore be assigned as the van der Waals radius of a covalently bound bromine atom. In similar ways, by making use of crystal structure data for many organic compounds, the van der Waals radii can be deduced. These values must be considered reliable to not more than about 5 pm, and this uncertainty makes itself evident in the range of values found for a particular element in different compounds and crystals. The values are sufficiently reliable, however, for scale drawings to be constructed and used to see hoe molecules can fit together. That van der Waals radii can be assigned with some success is attributable to the fact, mentioned, that the repulsive forces set in very strongly i.e. the potential energy curve raised very steeply, as atoms approach each other. It follows that even when rather different attractive forces operate, the closeness of approach is affected little.


2125_Vander waals.png

   Related Questions in Chemistry

  • Q : Neutralisation of phosphorous acids

    Provide solution of this question. To neutralise completely 20 mL of 0.1 M aqueous solution of phosphorous acid (H3 PO3) the volume of 0.1 M aqueous KOH solution required is: (a) 40 mL (b) 20 mL (c) 10 mL (d) 60 mL

  • Q : Colligative effect Choose the right

    Choose the right answer from following. Which one of the statements written below concerning properties of solutions, explain a colligative effect: (a) Boiling point of pure water decreases by the addition of ethano (b) Vapour pressure of pure water d

  • Q : Normality of solution containing

    Can someone please help me in getting through this problem. Determine the normality of a solution having 4.9 gm H3PO4 dissolved in 500 ml water: (a) 0.3  (b) 1.0  (c) 3.0   (d) 0.1

  • Q : Statement of Henry law Determine the

    Determine the correct regarding Henry’s law: (1) The gas is in contact with the liquid must behave as an ideal gas (2) There must not be any chemical interaction among the gas and liquid (3) The pressure applied must be high (4) All of these.

  • Q : Mole fraction of solute The mole

    The mole fraction of the solute in 1 molal aqueous solution is: (a) 0.027 (b) 0.036 (c) 0.018 (d) 0.009What is the correct answer.

  • Q : Determining maximum Osmotic pressure

    Which of the following would have the maximum osmotic pressure (assume that all salts are 90% dissociated): (a) Decimolar aluminium sulphate (b) Decimolar barium chloride (c) Decimolar sodium sulphate (d) A solution obtained by mix

  • Q : Solution density of water is 1g/mL.The

    density of water is 1g/mL.The concentration of water in mol/litre is

  • Q : Problem related to molality Help me to

    Help me to solve this problem. What is the molality of a solution which contains 18 g of glucose (C6,H12, O6) in 250 g of water:  (a) 4.0 m (b) 0.4 m (c) 4.2 m (d) 0.8 m

  • Q : Liquid surfaces The surface between a

    The surface between a liquid and a vapour distinguishes these fluids. The surface tension of liquids can be looked upon as that the property which draws a liquid together and forms a liquid vapour interface, therefore, distinguishing liquids from gases.<

  • Q : How haloalkanes are prepared from

    Alkyl halides can be prepared from alkanes through substitution and from alkenes through addition of halogen acids or through allylic substitution.    From alkanesWhen alkanes are treated with halogens, chlo