Ways in which Java program is less likely to be compromised
Give two ways in which a Java program is less likely to be compromised than the same program written in C++.
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In Java, Primitive and reference data types always passed by value while as in C++ referenced data types are passed by reference.
In Java, we have automatic garbage collection that doesn’t have the concept of Destructor and usage of finalize() is not recommended while have we have to explicitly rely upon destructors and deletete operator to free unused memory.
Macro in C: Macros are defined as single identifier
Explain the different ways in order to select the HTML Tag Instances.
Blank final variable: A final variable which is not initialized as portion of its declaration. This variable should be initialized in either an instance initialization block or every of the constructors for its class before it is employed. A static bl
Describe the term short lock in the tibco iProcess in brief.
Conditional operator: It is an operator taking three operands that is, a ternary operator. The conditional operator (?:) is employed in the form bexpr ? expr1 : expr2 Q : Define Mixed Mode Mixed Mode : Permits Mixed Mode: Permits domain controllers executing both Windows 2000 and prior versions of Windows NT to co-exist in the domain. In mixed mode, the domain features from prior versions of Windows NT Server are still allowed, whereas some Windows 2000 fea
Mixed Mode: Permits domain controllers executing both Windows 2000 and prior versions of Windows NT to co-exist in the domain. In mixed mode, the domain features from prior versions of Windows NT Server are still allowed, whereas some Windows 2000 fea
Software reuse: It is the ability to reuse software components in various contexts. The object-oriented languages aid to encourage reuse by their support of encapsulation.
What is the advantage of wrapping database calls in MTS transactions?
Write two programs to calculate the summation of 1 to some integer n using a function called int summation(int n) a) Using a non recursive solution, with a for(i=1, i<=n; i++) loop and b) using a recursive solution, based on the following conditions summation(n) = summation(n-1
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