Vant Hoff factor
The Van't Hoff factor of the compound K3Fe(CN)6 is: (a) 1 (b) 2 (c) 3 (d) 4 Answer: (d) K3[Fe(CN)6] → 3K+ + [Fe(CN)6]3-
The Van't Hoff factor of the compound K3Fe(CN)6 is:
(a) 1 (b) 2 (c) 3 (d) 4 Answer: (d) K3[Fe(CN)6] → 3K+ + [Fe(CN)6]3-
Describe the importance of organic chemistry?
Give me answer of this question. For a dilute solution, Raoult's law states that: (a) The lowering of vapour pressure is equal to mole fraction of solute (b) The relative lowering of vapour pressure is equal to mole fraction of solute (c) The relative lowering of v
The number of molecular orbitals and molecular motions of each symmetry type can be deduced. Let us continue to use the C2v point group and the H2O molecule to illustrate how the procedure develop
Illustrate HCl is polar or non-polar?
Describe all the kinds of insulators which are present?
Give me answer of this question. The atmospheric pressure is sum of the: (a) Pressure of the biomolecules (b) Vapour pressure of atmospheric constituents (c) Vapour pressure of chemicals and vapour pressure of volatile (d) Pressure created on to atmospheric molecules
The various elements
The equilibrium constant can be treated as a particular type of molecular distribution. Consider the simplest gas-phase reaction, one in which molecules of A are converted to molecules of B. the reaction, described by the equation Q : Moles of chloride ion Select the right Select the right answer of the question. A solution of CaCl2 is 0.5 mol litre , then the moles of chloride ion in 500ml will be : (a) 0.25 (b) 0.50 (c) 0.75 (d)1.00
Select the right answer of the question. A solution of CaCl2 is 0.5 mol litre , then the moles of chloride ion in 500ml will be : (a) 0.25 (b) 0.50 (c) 0.75 (d)1.00
Normal butane (C4H10) is stored as a compressed liquid at 90°C and 1400 kPa. In order to use the butane in a low-pressure gas-phase process, it is throttled to 150 kPa and passed through a vaporizer. The butane emerges from the vaporizer as a
18,76,764
1928348 Asked
3,689
Active Tutors
1433513
Questions Answered
Start Excelling in your courses, Ask an Expert and get answers for your homework and assignments!!