--%>

Strength of Nacl in solution

To 5.85gm of Nacl one kg of water is added to prepare of solution. What is the strength of Nacl in this solution (mol. wt. of nacl = 58.5)?

(a) 0.1 Normal (b) 0.1 Molal (c) 0.1 Molar (d) 0.1 Formal

Answer: (b) 5.85 g NaCl = 0.1 mol as it present in 1 kg of water
molality = wt./(m wt. x l) = 5.85/(58.5 x 1) = 0.1 molal  

   Related Questions in Chemistry

  • Q : Gibberella fusarium in bioremediation

    in bioremediation gibberella fusarium is used to break down____?

  • Q : Electron Spin The total angular

    The total angular momentum of an atom includes an electron spin component as well as an orbital component.The orbital motion of each electron of an atom contributes to the angular momentum of the atom, as described earlier. An additional

  • Q : Number of moles present in water

    Provide solution of this question. How many moles of water are present in 180 of water: (a)1 mole (b)18 mole (c)10 mole (d)100 mole

  • Q : Relationship between free energy and

    The free energy of a gas depends on the pressure that confines the gas. The standard free energies of formation, like those allow predictions to be made of the possibility of a reaction at 25°C for each reagent at 

  • Q : Haloalkanes define primary secondary

    define primary secondary and tertiary alkyl halides with examples

  • Q : Question on colligative property Choose

    Choose the right answer from following. Which of the following is a colligative property: (a) Osmotic pressure (b) Boiling point (c) Vapour pressure (d) Freezing point

  • Q : What type of bond does HCl encompass

    What type of bond does HCl encompass? Describe briefly?

  • Q : What are Vander Waal's Radii? Vander

    Vander Waal's radii can be assigned to the atoms of molecules on the basis of the closeness of approach of these atoms in crystalline substances. Diffraction studies of crystals give information about hoe molecules can approach each other and can pack

  • Q : Vapour pressure over mercury Choose the

    Choose the right answer from following. At 300 K, when a solute is added to a solvent its vapour pressure over the mercury reduces from 50 mm to 45 mm. The value of mole fraction of solute will be: (a)0.005 (b)0.010 (c)0.100 (d)0.900

  • Q : Question on Raoults law Give me answer

    Give me answer of this question. For a dilute solution, Raoult's law states that: (a) The lowering of vapour pressure is equal to mole fraction of solute (b) The relative lowering of vapour pressure is equal to mole fraction of solute (c) The relative lowering of v