State substituted hydrocarbon
Elaborate a substituted hydrocarbon?
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The substituted hydrocarbon is a hydrocarbon with one or more of hydrogen is substituted with other element, (every so often a halogen like as bromine or chlorine) or other group of atoms as -OH. Such as: - The simple hydrocarbon is methane (CH4). Substitute chlorine for the hydrogen to get Methyl Chloride (CH3Cl) is used for cleaning. Sub to get- Methylene Chloride (CH2Cl2) is used as a paint stripper. Sub to get- Chloroform (CHCl3) is an antique anaesthetic. Sub to get- Carbon Tetrachloride (CCl4) is used in the fire extinguishers and cleaning. Substitute single -OH group into the - CH4 to get methanol (CH3OH) or into C2H6 to get ethanol (C2H5OH) The above instances all begin with the unbranched non-cyclic hydrocarbons, but any hydrocarbon is an appropriate target. A known instance is a double replacement of chlorine at the opposite ends of the benzene ring to form paradichlorbenzene, normally found hanging in toilet bowls. C6H6 becomes C6H4Cl2
Provide solution of this question. 1.0 gm of pure calcium carbonate was found to need 50 ml of dilute HCL for complete reaction. The strength of the HCL solution is specified by : (a) 4 N (b) 2 N (c) 0.4 N (d) 0.2 N
The colligative properties of a solution depend on: (a) Nature of solute particles present in it (b) Nature of solvent used (c) Number of solute particles present in it (d) Number of moles of solvent only
Choose the right answer from following. Molar concentration (M) of any solution : a) No. of moles of solute/Volume of solution in litre (b) No. of gram equivalent of solute / volume of solution in litre (c) No. of moles os solute/ Mass of solvent in kg (
Atomic orbitals can be combined, in a process called hybridization, to describe the bonding in polyatomic molecules. Descriptions of the bonding in CH4 can be used to illustrate the valence bond procedure. We must arrive a
The boiling point of 0.1 molal aqueous solution of urea is 100.18oC at 1 atm. The molal elevation constant of water is: (a) 1.8 (b) 0.18 (c) 18 (d) 18.6Answer: (a) Kb
Help me to go through this problem. When 7.1gm Na2SO4 (molecular mass 142) dissolves in 100ml H2O , the molarity of the solution is: (a) 2.0 M (b) 1.0 M (c) 0.5 M (d) 0.05 M
How many electrons are present in a benzene?
To 5.85gm of Nacl one kg of water is added to prepare of solution. What is the strength of Nacl in this solution (mol. wt. of nacl = 58.5)? (a) 0.1 Normal (b) 0.1 Molal (c) 0.1 Molar (d) 0.1 FormalAnswer:
The free energy of a component of a liquid solution is equal to its free energy in the equilibrium vapour.Partial molal free energies let us deal with the free energy of the components of a solution. We use these free energies, or simpler concentration ter
To meet human needs, scientists have started preparing synthetic rubbers. Besides having similar properties as natural rubbers they are tougher, more flexible and more durable than natural rubber. They are capable of getting stretched to twice its length. Though, it reverts to its original shape
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