State substituted hydrocarbon
Elaborate a substituted hydrocarbon?
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The substituted hydrocarbon is a hydrocarbon with one or more of hydrogen is substituted with other element, (every so often a halogen like as bromine or chlorine) or other group of atoms as -OH. Such as: - The simple hydrocarbon is methane (CH4). Substitute chlorine for the hydrogen to get Methyl Chloride (CH3Cl) is used for cleaning. Sub to get- Methylene Chloride (CH2Cl2) is used as a paint stripper. Sub to get- Chloroform (CHCl3) is an antique anaesthetic. Sub to get- Carbon Tetrachloride (CCl4) is used in the fire extinguishers and cleaning. Substitute single -OH group into the - CH4 to get methanol (CH3OH) or into C2H6 to get ethanol (C2H5OH) The above instances all begin with the unbranched non-cyclic hydrocarbons, but any hydrocarbon is an appropriate target. A known instance is a double replacement of chlorine at the opposite ends of the benzene ring to form paradichlorbenzene, normally found hanging in toilet bowls. C6H6 becomes C6H4Cl2
Can someone please help me in getting through this problem. Concentrated H2SO4 has a density of 1.98 gm/ml and is 98% H2SO4 by weight. The normality is: (a) 2 N (b) 19.8 N (c) 39.6 N (d) 98
The molality of a solution will be: (i) Number of moles of solute per 1000 ml of solvent (ii) Number of moles of solute per 1000 gm of solvent (iii) Number of moles of solute per 1000 ml of solution (iv) Number of gram equivalents of solute per 1000 m
Enzymes are complex proteinous substances, produced by living bodies, such as act as catalysis in the physiological reactions. The enzymes are, also called biochemical catalysts and the phenomenon is known as bio-chemical catalysis because numerous reactions that occur the bodies of animals and p
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Provide solution of this question.10N/and 1/10N solution is called: (a) Decinormal and decanormal solution (b) Normal and decinormal solution (c) Normal and decanormal solution (d) Decanormal and decinormal solution
Can someone please help me in getting through this problem. Two solutions of a substance (that is, non electrolyte) are mixed in the given manner 480 ml of 1.5M first solution + 520 ml of 1.2M second solution. Determine the molarity of the final mixture
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