State substituted hydrocarbon
Elaborate a substituted hydrocarbon?
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The substituted hydrocarbon is a hydrocarbon with one or more of hydrogen is substituted with other element, (every so often a halogen like as bromine or chlorine) or other group of atoms as -OH. Such as: - The simple hydrocarbon is methane (CH4). Substitute chlorine for the hydrogen to get Methyl Chloride (CH3Cl) is used for cleaning. Sub to get- Methylene Chloride (CH2Cl2) is used as a paint stripper. Sub to get- Chloroform (CHCl3) is an antique anaesthetic. Sub to get- Carbon Tetrachloride (CCl4) is used in the fire extinguishers and cleaning. Substitute single -OH group into the - CH4 to get methanol (CH3OH) or into C2H6 to get ethanol (C2H5OH) The above instances all begin with the unbranched non-cyclic hydrocarbons, but any hydrocarbon is an appropriate target. A known instance is a double replacement of chlorine at the opposite ends of the benzene ring to form paradichlorbenzene, normally found hanging in toilet bowls. C6H6 becomes C6H4Cl2
The objective of this work is to separate a binary mixture and to cool down the bottom product for storage. (Check table below to see which mixture you are asked to study). 100 kmol of feed containing 10 mol percent of the lighter component enters a continuous distillation column at the m
Choose the right answer from following. Volume of water needed to mix with 10 ml 10N NHO3 to get 0.1 N HNO3: (a) 1000 ml (b) 990 ml (c) 1010 ml (d) 10 ml
When the catalyst exists in a different phase than that of reactants, it is said to be heterogeneous catalyst, and the catalysis is called heterogeneous catalysis. For example, SO2 can be oxidized to SO3
order of decreasing basicity of urea and its substituents
Select the right answer of the question. A solution of CaCl2 is 0.5 mol litre , then the moles of chloride ion in 500ml will be : (a) 0.25 (b) 0.50 (c) 0.75 (d)1.00
Give me answer of this question. A solution has a 1 : 4 mole ratio of pentane to hexane. The vapour pressure of the pure hydrocarbons at 20°C are 440 mmHg for pentane and 120 mmHg for hexane. The mole fraction of pentane in the vapour phase would be: (a) 0.549 (b)
Provide solution of this question. Molarity of a solution prepared by dissolving 75.5 g of pure KOH in 540 ml solution is: (a) 3.05 M (b) 1.35 M (c) 2.50 M (d) 4.50 M
Can someone please help me in getting through this problem. The solution ofAl2(SO4)3 d = 1.253gm/m comprise 22% salt by weight. The molarity, normality and molality of the solution is: (1) 0.805 M, 4.83 N, 0.825 M (2)
What weight of hydrated oxalic acid should be added for complete neutralisation of 100 ml of 0.2N - NaOH solution? (a) 0.45 g (b)0.90 g (c) 1.08 g (d) 1.26 g Answer
changes in matter law of chemical combination
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