Problem on multi level TDM

Ten sources, six with a bit rate of 200 Kbps and four with a bit rate of 400Kbps are to be combined using multi level TDM with no sync bits. Answer the questions below about the final phase of multiplexing:

a. Find out the size of a frame in bits?

b. Find out the frame rate?

c. Evaluate the duration of a frame?

d. Determine the data rate?

View Complete Question

Comments & Conversion

Expert

Verified

Combine six 200-kbps sources into three 400-kbps. So there are seven 400-kbps channels.

a. All output frames carry 1 bit from each of the seven 400-kbps line. Frame size = 7 × 1 = 7 bits.

b. All frame carry 1 bit from each 400-kbps source. Frame rate = 400,000 frames/s.

c. Frame duration = 1 /(frame rate) = 1 /400,000 = 2.5 μs.

d. Output data rate = (400,000 frames/s) × (7 bits/frame) = 2.8 Mbps.

Related Questions in Physics

Q : Define Josephson effects Josephson

Josephson effects (B.D. Josephson; 1962): Electrical effects examined whenever two superconducting materials are separated by a thin layer of the insulating substance.

Q : What do you mean by the term density

What do you mean by the term density? Briefly explain it.

Q : Define Centrifugal pseudo force

Centrifugal pseudo force: A pseudo force which takes place whenever one is moving in uniform circular motion. One feels a "force" directed outward from the center of the motion.

Q : Scanning electron and transmission

Give one benefit of a scanning electron microscope over the transmission electron microscope? Briefly explain it.

Q : Acceleration during this interval The

The velocity of a body was observed to be constant throughout five minutes of its motion. Determine its acceleration during this interval?

Q : Explain avogadro's hypothesis

Avogadro's hypothesis (Count A. Avogadro; 1811): Equivalent volumes of all gases at similar temperature and pressure contain equivalent numbers of molecules. This is, in fact, true only for the ideal gases. <

Q : Calculate the concentration A

A dual-wavelength spectrometer uses 780 nm and 830 nm. The molar extinction coefficients for oxy-hemoglobin (HbO2) and deoxy-hemoglobin (Hb) at these two wavelengths are: e_HbO2_780nm = 710 cm-1M-1, e_Hb_780nm = 1075 cm

Q : Secondary electron image and back

What is main difference between secondary electron image and the back scattered electron image? State briefly.

Q : Explain Thomson experiment or Kelvin

Thomson experiment: Kelvin effect (Sir W. Thomson [later Lord Kelvin]): Whenever an electric current flows via a conductor whose ends are maintained at various temperatures, heat is discharged at a rate just about proportional to the

Q : Explain Planck radiation law Planck

Planck radiation law: The law which explained blackbody radiation better than its precursor, therefore resolving the ultraviolet catastrophe. This is based on the supposition that electromagnetic radiation is quantized.

Discover Q & A

Leading Solution Library

Avail More Than 1425612 Solved problems, classrooms assignments, textbook's solutions, for quick Downloads

No hassle, Instant Access

Start Discovering

18,76,764

1954676
Asked

3,689

Active Tutors

1425612

Questions
Answered

Start Excelling in your courses, Ask an Expert and get answers for your homework and assignments!!

Submit Assignment