Problem on MM equation
How to obtain relation between Vm and Km,given k(sec^-1) = Vmax/mg of enzyme x molecular weight x 1min/60 sec S* = 4.576(log K -10.753-logT+Ea/4.576T).
Expert
According to M.M Equation, V = Vmax x {S]/Km + {S] Since Vmax = ksec^-1 {Et}V = Ksec^-1{Et} x {S}/Km + {S}Substituting the given value of Ksec^-1 in the above equation,we get V = Vmax x mol.wt x 1min/60 sec x {S}/mg of enzyme / Km +{S]V = Vmax x mol.wt x {S}/mg of enzyme/Km +{S}Substituting the given value of {S}V = Vmax x mol.wt x 4.576(log K -10.753-logT+Ea/4.576T)/mg of enzyme/ Km + 4.576(log K -10.753-logT+Ea/4.576T)
is entropy on moleculare basis relates to the tras.,vib.,and rotational motions?
parachloroaniline is strong base than paranitroaniline
Illustrate the Lewis Dot Structure for the CH4O.
Briefly describe the dipole moment direction for the methanol?
Can someone please help me in getting through this problem. The mole fraction of water in 20% aqueous solution of H2O2 is: (a) 77/68 (b) 68/77 (c) 20/80 (d) 80/20
Briefly describe the procedure for separating the components of the gun-powder?
Determination of correct mol. Mass from Roult's law is applicable to :
Unit of measurement- These are also some systems for units: (1)
Give me answer of this question. The concentration of an aqueous solution of 0.01M CH3OH solution is very nearly equal to which of the following : (a) 0.01%CH3OH (b) 0.1%CH3OH (c) xCH3OH= 0.01 (d) 0.99MH2O (
Which of the following solutions will have a lower vapour pressure and why? a) A 5% aqueous solution of cane sugar. b) A 5% aqueous solution of urea.
18,76,764
1949888 Asked
3,689
Active Tutors
1461357
Questions Answered
Start Excelling in your courses, Ask an Expert and get answers for your homework and assignments!!