Problem on flow rate of natural gas
Natural Gas is flowing through a 10 inch schedule 40 pipe. The gas is at 109°F and 7.3 psig. The outside air temperature is 92°F. If the flow rate of the gas is 8,000 SCFM: What is the flow rate in lb/hr?
Expert
The cross sectional Area of the Pipe
= (22/7)*((power(10.75,2)-power(10.02,2))= 47.65231429*0.00694444444=0.330918849sq ft
Now the volumetric flow rate 8000 SCFM means 8000 cubic ft
PV=nRT
P=7.3 psig=7.3+14.7 psi =22psi=22*6894.75729 pa
=151684.6604Pa
V=8000 cuft V=8000*0.0283168466 cubic meters=226.5347728 Cu m
Temp =306.4833K
N= 151684.6604Pa*226.5347728 Cu m/(8.314J/K-mole*306.4833K)= 13485.27177 mole
Considering the Nutral gas is methane CH4 =16kg/mole
So Mass flow rate =215764.3484Kg/Hr =475678.9634lb/hr
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A stream of propane is throttled from 4.298 bar and 450 K to 0.22 bar. This process is irreversible due to frictional losses at the nozzle. a. In words or equations, why are frictional losses irreversible? Discover Q & A Leading Solution Library Avail More Than 1440310 Solved problems, classrooms assignments, textbook's solutions, for quick Downloads No hassle, Instant Access Start Discovering 18,76,764 1952947 Asked 3,689 Active Tutors 1440310 Questions Answered Start Excelling in your courses, Ask an Expert and get answers for your homework and assignments!! Submit Assignment
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