Problem based on lowering in vapour pressure
Help me to solve this problem. An aqueous solution of glucose was prepared by dissolving 18 g of glucose in 90 g of water. The relative lowering in vapour pressure is: (a) 0.02 (b)1 (c) 20 (d)180
Provide solution of this question. While 1.80gm glucose dissolve in 90 of H2O , the mole fraction of glucose is: (a) 0.00399 (b) 0.00199 (c) 0.0199 (d) 0.998
Briefly describe the difference in the Mendeleev’s table and modern periodic table?
Choose the right answer from following. The normality of 10 lit. volume hydrogen peroxide is: (a) 0.176 (b) 3.52 (c) 1.78 (d) 0.88 (e)17.8
Choose the right answer from following. The molarity of pure water is: (a) 55.6 (b) 5.56 (c)100 (d)18
why o-toluidine is a weaker base than aniline?
Illustrate the dipole moment of chlorooctane?
What type of bond does HCl encompass? Describe briefly?
Relative humidity is the ratio of the partial pressure of water in air to the partial pressure of water in air saturated with water at the same temperature, stated as a percentage: Relative = Q : Oxoacids of halogens Why oxidising Why oxidising character of oxoacids of halogens decreases as oxidation number increases?
Why oxidising character of oxoacids of halogens decreases as oxidation number increases?
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