normality
how 0.5N HCL is prepared for 10 littre solution
Many enzyme catalyzed reactions obeys a complex rate equation that can be written as the total quantity of enzyme and the whole amount of substrate in the reaction system. Many rate equations that are more complex than first and se
If a electron is present in place of anion in a crystal lattice, then it is termed as: (a) Frenkel defect (b) Schottky defect (c) Interstitial defects (d) F-centre Answer: (d) When electrons are trapped in anion vacancies, thes
Select the right answer of the following question.What does not change on changing temperature : (a) Mole fraction (b) Normality (c) Molality (d) None of these
Describe the dipole moment of chloro-octane in brief?
20 g of hydrogen is present in 5 litre of vessel. Determine he molar concentration of hydrogen: (a) 4 (b) 1 (c) 3 (d) 2 Choose the right answer from above.
: 1) Chromium(III) hydroxide is highly insoluble in distilled water but dissolves readily in either acidic or basic solution. Briefly explain why the compound can dissolve in acidic or in basic but not in neutral solution. Write appropriate equations to
Can we demonstration the organic structure of cetearyl alcohol and state me what organic family it is?
. Boiling pointsThe boiling points of monohalogen derivatives of benzene, which are all liquids, follow the orderIodo > Bromo > ChloroThe boiling points of isomeric dihalobe
Choose the right answer from following. If P and P are the vapour pressure of a solvent and its solution respectively N1 and N2 and are the mole fractions of the solvent and solute respectively, then correct relation is: (a) P= PoN1 (b) P= Po N2 (c)P0= N2 (d)
Give me answer of this question. When a non-volatile solute is dissolved in a solvent, the relative lowering of vapour pressure is equal to: (a) Mole fraction of solute (b) Mole fraction of solvent (c) Concentration of the solute in grams per litre (d) Concentratio
18,76,764
1946743 Asked
3,689
Active Tutors
1416295
Questions Answered
Start Excelling in your courses, Ask an Expert and get answers for your homework and assignments!!