Neutralization of sodium hydroxide
How much of NaOH is needed to neutralise 1500 cm3 of 0.1N HCl (given = At. wt. of Na =23): (i) 4 g (ii) 6 g (iii) 40 g (iv) 60 g
Expert
The answer is (ii)
1500cm3 of .01 N HCL have number of gm equivalence
= N1 x V1/ 1000 = 1500x0.1/ 1000 = 0.15
0.15 gm. Equivalent of NaOH = 0.15 x 40 = 6 gm
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37% weight of HCl and density is 1.1g/ml. find molarity of HCl
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