Negative deviation
Which one of the following non-ideal solutions shows the negative deviation: (a) CH3COCH3 + CS2 (b) C6H6 + CH3COCH3 (c) CCl4 + CHCl3 (d) CH3COCH3 + CHCl3Answer: (d) CH3COCH3 + CHCl3 is non ideal solution which shows negative deviation.
Illustrate all the explosions produce carbon dioxide?
is entropy on moleculare basis relates to the tras.,vib.,and rotational motions?
Choose the right answer from following. 200ml of a solution contains 5.85 dissolved sodium chloride. The concentration of the solution will be(Na= 23: cl = 35.5 ) (a) 1 molar (b) 2 molar (c) 0.5 molar (d) 0.25 molar
In a liquid a solid substance a molecule present within the bulk of the substance is being attracted infirmly from all sides by the neighbouring molecules. Hence there is no bet force acting on the molecule or there are no unbalanced forces of the molecule. On the oth
The occurrence of different phases of a one component system can be shown on a pressure temperature. The phases present in a one line system at various temperatures can be conveniently presented on a P- versus-T diagram. An example is pro
Give me answer of following question. The sum of the mole fraction of the components of a solution is : (a) 0 (b) 1 (c) 2 (d) 4.
arrange in decreasing order of basicity pi pyridine,pyridine,pyrrole, morphine
An example illustrates the type of mechanism that can be written to explain the development of flash photolysis reactions. Often, as the reactions in the ozone layer of the earth's atmosphere, we are interested in the kinetic behavior of species that are not a
The objective of this work is to separate a binary mixture and to cool down the bottom product for storage. (Check table below to see which mixture you are asked to study). 100 kmol of feed containing 10 mol percent of the lighter component enters a continuous distillation column at the m
Describe how dipole attractions, London dispersion forces and the hydrogen bonding identical?
18,76,764
1941274 Asked
3,689
Active Tutors
1414589
Questions Answered
Start Excelling in your courses, Ask an Expert and get answers for your homework and assignments!!