Molarity of HCl solution
20 ml of HCL solution needs 19.85 ml of 0.01M NaOH solution for complete neutralization. Morality of the HCL solution is: (i) 0.0099 (ii) 0.099 (iii) 0.99 (iv) 9.9 Choose the right answer from above.
20 ml of HCL solution needs 19.85 ml of 0.01M NaOH solution for complete neutralization. Morality of the HCL solution is: (i) 0.0099 (ii) 0.099 (iii) 0.99 (iv) 9.9
Choose the right answer from above.
Expert
The right answer is (i)
M1V1 = M2V20.01 x 19.85 = M2 x 20M2= 0.00925 : M : 0.0099
The main objective of this particular aspect of Physical Chemistry is to examine the relation between free energies and the mechanical energy of electromotive force of electrochemical cells. The ionic components of aqueous solutions can be treated on the basis of the
show how a mathematical definition of entropy can be obtauined from a consideration of carnot cycle?
lculwhat is the equation for caating molar mass of non volatile solute
which is largest planet in our solar system
Choose the right answer from following. While 90 gm of water is mixed with 300 gm of acetic acid. The total number of moles will be: (a)5 (b)10 (c)15 (d)20
Avogadro's hypothesis Law Principle- Berzelius, a chemist tried
What is the utilization of glacial acetic acid? Briefly describe the uses.
Help me to go through this problem. The distribution law is applied for the distribution of basic acid between : (a) Water and ethyl alcohol (b) Water and amyl alcohol (c) Water and sulphuric acid (d) Water and liquor ammonia
Emulsions are colloidal solutions in which disperse phase as well as dispersion medium is both liquids. Emulsions can be broadly classified into two types: (i) Oil in water (O/W type) emulsions: in this type of emulsions, oil acts disperse phase and water acts
The occurrence of different phases of a one component system can be shown on a pressure temperature. The phases present in a one line system at various temperatures can be conveniently presented on a P- versus-T diagram. An example is pro
18,76,764
1945307 Asked
3,689
Active Tutors
1419598
Questions Answered
Start Excelling in your courses, Ask an Expert and get answers for your homework and assignments!!