The freezing point of a solution having 4.8 g of a compound in 60 g of benzene is 4.48. Determine the molar mass of the compound (Kf = 5.1 Km-1) , (freezing point of benzene = 5.5oC)
(a) 100 (b) 200 (c) 300 (d) 400
Answer: (d) m = (Kf x 1000 x w)/W x ΔTf = (5.1 x 1000 x 4.80)/(60 x 1.02) = 400