--%>

Liquid surfaces

The surface between a liquid and a vapour distinguishes these fluids.


The surface tension of liquids can be looked upon as that the property which draws a liquid together and forms a liquid vapour interface, therefore, distinguishing liquids from gases.

The molecular basis for this property is suggested, where the unbalanced attractions experienced by the surface molecules are shown to lead to the amount of free liquid will pull it together to form a less spherical drop. The surface layer can be expected to have properties that differ from those of the bulk of the liquid.

The surface tension of the liquid can be defined with reference to where it is most easily pictured is a wire frame, arranged as a piston, used to expand a soap film. The definition also applies to the mechanically more difficult systems where the film is replaced by a layer of liquid of appreciable thickness. The force required stretching the film or liquid vapour is proportional to the length l of the piston. Since there are two surfaces of the film, the total length of the film is 2l, and the proportionality equation:

ƒ = γ(2l) can be written.

The proportionality constant γ is known as the surface tension, and according to the above equation it can be looked upon as the force by a surface of unit length.
Of more general use is the relation between surface tension and surface energy. The mechanical energy required to expand the surfaces by moving the piston a distance dx is f dx, or 2l dx. Since the area of new surface is 2l dx, the result:

Mechanical energy/change of surface area = 2lγ dx/ 2l dx = γ, can be obtained. This expression shows that the surface tension can be interpreted as the energy per unit surface area and that it is a mechanical rather than thermal energy. In these terms, the tendency of a surface to reduce its area is just another example of a system tending toward an arrangement of low free energy.

Surface tension of some liquids, N m-1:

Liquid 20°C 60°C 100°C Liquid t, °C Surface tension
H2O 0.07275 0.06618 0.05885 Hg 0 0.480
C2H5OH 0.0223 0.0223 0.0190 Ag 970 0.800
C6H6 0.0289 0.0237   NaCl 1080 0.094
(C2H5)2O 0.0170   0.0080 AgCl 452 0.125


Example: compare the heights to which water and carbon tetrachloride will rise as a result of capillary action in a tube with an internal diameter of 0.1 mm. at 20°C the surface tensions of water and carbon tetrachloride, respectively, are 0.0727 and 0.0268 N m-1, and their densities are 0.998 and 1.595 g mL-1.

Solution: 
we use to obtain:

L = 2 γ/rpg


The radius of the cube is 0.5 mm = 0.5 × 10-4 m, and the densities are 9.98 × 103 and 1.598 × 103 kg m-3.

For water: l = 2 (0.0727 N m-1)/(0.5 × 10-4 m) (9.98 × 103 kg m-3) (9.81 m s-1)

= 0.0297 m = 29.7 mm

For CCl4: l = 2 (0.0268 N m-1)/(0.5 × 10-4 m) (1.595 × 103 kg m-3) (9.81 m s-2)

= 0.00685 m = 6.85 mm.

   Related Questions in Chemistry

  • Q : What is solvent dielectric effect?

    Ionic dissociation depends on the dielectric constant of the solvent.The Arrhenius that ions are in aqueous solutions in equilibrium with parent molecular species allows many of the properties of ionic solutions to be understood. But difficulties began to

  • Q : Polymers comparison of biodegradable

    comparison of biodegradable and non-biodegradable polymers

  • Q : Question on seminormal solution Provide

    Provide solution of this question. The weight of sodium carbonate required to prepare 500 ml of a seminormal solution is: (a) 13.25 g (b) 26.5 g (c) 53 g (d) 6.125 g

  • Q : Benzoic acid is weaker than paranitro

    Briefly state that Benzoic acid is weaker than paranitro benzoic acid?

  • Q : Problem on mole fraction of glucose

    Provide solution of this question. While 1.80gm glucose dissolve in 90 of H2O , the mole fraction of glucose is: (a) 0.00399 (b) 0.00199 (c) 0.0199 (d) 0.998

  • Q : Linde liquefaction process Liquefied

    Liquefied natural gas (LNG) is produced using a Linde liquefaction process from pure methane gas at 3 bar and 280 K (conditions at point 1 in figure below). A three-stage compressor with interceding is used to compress the methane to 100 bar (point 2). The first stage

  • Q : Molarity of Nacl solution When 5.85 g

    When 5.85 g of NaCl (having molecular weight 58.5) is dissolved in water and the solution is prepared to 0.5 litres, the molarity of the solution is: (i) 0.2 (ii) 0.4 (iii) 1.0 (iv) 0.1

  • Q : Statement of Henry law Determine the

    Determine the correct regarding Henry’s law: (1) The gas is in contact with the liquid must behave as an ideal gas (2) There must not be any chemical interaction among the gas and liquid (3) The pressure applied must be high (4) All of these.

  • Q : Group Cations Explain how dissolving

    Explain how dissolving the Group IV carbonate precipitate with 6M CH3COOH, followed by the addition of extra acetic acid, establishes a buffer with a pH of approximately

  • Q : Hybridization Atomic orbitals can be

    Atomic orbitals can be combined, in a process called hybridization, to describe the bonding in polyatomic molecules. Descriptions of the bonding in CH4 can be used to illustrate the valence bond procedure. We must arrive a