--%>

Laws of Chemical Combination

Laws of Chemical Combination- In order to understand the composition of the compounds, it is necessary to have a theory which accounts for both qualitative and quantitative observations during chemical changes. Observations of chemical reactions were most significant in the development of a satisfactory theory of the nature of matter. These observations of chemical reactions are summarized in certain statements known as laws of chemical combination. These are:

1-Law of conservation of mass

2-Law of constant composition

3-Law of multiple proportions

4-Law of reciprocal proportion

5-Law of combining volumes (Gay Lussac's law of gaseous volume)

1-Law of conservation of mass-This law deals with the masses of reactant & the products of any chemical reaction (or a physical change).It was studied by French chemist Antoine Lavoisier. This law may be stated as follow-In all the chemical & physical changes, the total mass of the reactants is equal to that of the products. . It is a derivation of Dalton's atomic theory 'atoms neither created nor destroyed'.

Total masses of [reactants=products+unreacted reactants]

For example-1-A piece of ice in flask (weighted) is heated gently to melt ice (solid) into water (liquid) & again weighted. It's found that there is no change in weight though a physical change has taken place.

2-If 5.2 g of CaCo2when heated produced 1.99 g of Carbon dioxide and the residue (CaO) left behind weighs 3.2g.

So the total weight of the products (CaO +CO2) = 3.20+ 1.99 = 5.19 g

 Difference between the wt. of the reactant and the total wt. of the products= 5.20 - 5.19 =0.01 g.

This small difference may be due to experimental error. Thus law of conservation of mass holds good with in experimental errors.

2-Law of constant composition or the definite proportions-This law was given by J.L.Proust & deals with the composition of elements present in a given compound. It states that- A chemical compound always contains same elements combined together in same proportion by mass. and it does not depend on the source of compound. For example-CO2 can be obtained by different method such as 

661_Law of constant composition.png

The composition of CO2 obtained by different means always having same C: O ratio =12/32 = 0.375 by mass.

Limitations of law of constant composition are-

(i)This law is not applicable if an element exists in different isotopes which may be involved in formation of compound.e.g.In the formation of CO2, if C-12 isotope & C-14 isotope combine than the C: O is 12:32 & 14:32 respectively.

(ii)The compounds formed may be different but the elements may combine in same ratio.

3-Law of multiple proportion: It was studied by Dalton, which defined as follow-

When two elements combine to form two or more than two different chemical compounds then the different masses of one element which combine with fixed mass of the other element bear a simple ratio to one another.

For example: Carbon forms two oxides in oxygen 

2190_Law of multiple proportion.png

 

The ratio of masses of oxygen in CO and CO2 for fixed mass of carbon (12) 
is 16 : 32 = 1: 2.

Similar with compounds of sulphur & oxygen-they also formed two oxides SO2 & SO3 so the ratio of masses of oxygen 32:48 or 2:3 respectively.

4-Law of reciprocal proportion: This law was given by Richter. It stated as follow-

If two elements combine separately with a fixed mass of a third element, then the ratio of their masses in which they do so is either same or multiple of the ratio in which they combine with each other. The above law is the basis of law of equivalent masses.

5-Law of combining volumes (Gay Lussac's law of gaseous volume) - It states that at a given temperature and pressure, when the gases combine they do so in volumes which bear a simple ratio to each other and also to the volume of gaseous product.

e.g. If one volume of hydrogen react with one volume of chlorine to form two volumes of hydrogen chloride gas. The ratio of volume of various reactant & product is 1:1:2 which is a simple whole number ratio. Similar in the formation of ammonia, the ratio of reactant nitrogen, hydrogen & ammonia is 1:3:2 which is a simple whole number ratio.

   Related Questions in Chemistry

  • Q : Problem on vapour pressure and mole

    Provide solution of this question. The vapour pressure of a solvent decreased by 10 mm of mercury, when a non-volatile solute was added to the solvent. The mole fraction of the solute in the solution is 0.2. What should be the mole fraction of the solvent, if decrea

  • Q : Explain solid in liquid solutions. The

    The French chemist Francois Marie Raoult (1886) carried out a series of experiments to study the vapour pressure of a number of binary solutions. On the basis of the results of the experiments, he proposed a generalization called Raoult's law which states that, <

  • Q : Question based on relative lowering of

    Give me answer of this question. When a non-volatile solute is dissolved in a solvent, the relative lowering of vapour pressure is equal to: (a) Mole fraction of solute (b) Mole fraction of solvent (c) Concentration of the solute in grams per litre (d) Concentratio

  • Q : Number of mlecules in methane Can

    Can someone please help me in getting through this problem. The total number of molecules in 16 gm of methane will be: (i) 3.1 x 1023 (ii) 6.02 x 1023 (iii) 16/6.02 x 1023 (iv) 16/3.0 x 1023

  • Q : Group Cations Explain how dissolving

    Explain how dissolving the Group IV carbonate precipitate with 6M CH3COOH, followed by the addition of extra acetic acid, establishes a buffer with a pH of approximately

  • Q : Volume of solution containing solute

    What volume of solution contains 0.1 mole of the solute: (a) 100ml (b) 125ml  (c) 500ml (d) 62.5ml Choose the right answer from above.

  • Q : What are emulsions?Describe its

    Emulsions are colloidal solutions in which disperse phase as well as dispersion medium is both liquids. Emulsions can be broadly classified into two types: (i) Oil in water (O/W type) emulsions: in this type of emulsions, oil acts disperse phase and water acts

  • Q : Molarity 20mol of hcl solution requires

    20mol of hcl solution requires 19.85ml of 0.01 M NAOH solution for complete neutralisation. the molarity of hcl solution

  • Q : Molar mass of solute The boiling point

    The boiling point of benzene is 353.23 K. If 1.80 gm of a non-volatile solute was dissolved in 90 gm of benzene, the boiling point is increased to 354.11 K. Then the molar mass of the solute is: (a) 5.8g mol-1  (b)

  • Q : What is Elevation in boiling point? The

    The boiling of a liquid may be defused by the temperature at which its vapour pressure which is equal to atmospheric pressure. The effect of addition in a non-volatile solute on the boiling point shown and its solution containing non-volatile solute with tempe