Ionic radius of chloride ion

The edge length of the unit cell of Nacl crystal lattice is 552 pm. If ionic radius of sodium ion is 95. What is the ionic radius of chloride ion:
(a) 190 pm (b) 368 pm (c) 181 pm (d) 276 pm

Answer: (c) Distance between centres of Na⁺ and Cl^-

r_Na⁺ + r_Cl^- = 276 pm or 95 + r_Cl^- = 276 pm

or r_Cl^- = 276 - 95 = 181 pm

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