I need to solve the material and energy balance
I need to solve the material and energy balance for the att.
A stream of steam at 1 bar and 400 K enters a compressor through a pipe with cross-sectional area of 0.1 m2 at a velocity of 5 m/s. The pressure of the outlet stream is at 5 bar, temperature is at 500 K, and velocity is 1 m/s. Assume the steam can be descri
The feed to an ammonia synthesis reactor contain 25 mole% nitrogen and the balance hydrogen. The flow rate of the stream is 3000 kg/hr. Calculate the rate of flow of nitrogen into the reactor in kg/hr. (Hint: First calculate the average molecular weight of the mixture).
Consider a chemical reaction: a CH3-CH=CH2 + b NH3 + c O2 → d CH2=CH-C≡N + e H2O 1. &
To determine the temperature that occurred in a ?re in a warehouse, the arson investigator noticed that the relief valve on a methane storage tank had popped open at 3000 psig, the rated value. Before the ?re started, the tank was presumably at ambient conditions and the gage read 1950 psig. If
You are asked to make up a laboratory solution of 0.10 molar H2SO4 from concentrated (96%) H2SO4 at 56°F. The barometric pressure reads 750 mmHg. You look up the specific gravity of 96% H2SO4 and find it is listed at 1.858. Calculate: (a) th
The feed of an ammonia synthesis reactor is 25% (lbmole) nitrogen with the balance hydrogen. The flow rate is 3000 kg/h at 65°C and 95 bar. Calculate the flow rate of nitrogen to the reactor in kg/hr.
I) Sulphur dioxide (SO2) with a volumetric flow rate 5000cm3/s at 1 bar and 1000C is mixed with a second SO2 stream flowing at 2500cm3/s at 2 bar and 200C. The process occurs at steady state. You may assume ideal gas behaviour. For SO2 take the heat capacity at constant pressure to be CP/R = 3.267+5
A stream of propane is throttled from 4.298 bar and 450 K to 0.22 bar. This process is irreversible due to frictional losses at the nozzle. a. In words or equations, why are frictional losses irreversible? Q : Problem on entropy A heater (heat A heater (heat source temperature = 527 K) and turbine are connected in series as shown below: Q : Problem on Clausius-Clapeyron equation The Clausius-Clapeyron equation gives us an expression for dP/dT. Now we will derive an analog to the Clausius-Clapeyron equation by obtaining an expression for dT/dµ when two phases are at equilibrium. For simplicity, let’s derive this fo
A heater (heat source temperature = 527 K) and turbine are connected in series as shown below: Q : Problem on Clausius-Clapeyron equation The Clausius-Clapeyron equation gives us an expression for dP/dT. Now we will derive an analog to the Clausius-Clapeyron equation by obtaining an expression for dT/dµ when two phases are at equilibrium. For simplicity, let’s derive this fo
The Clausius-Clapeyron equation gives us an expression for dP/dT. Now we will derive an analog to the Clausius-Clapeyron equation by obtaining an expression for dT/dµ when two phases are at equilibrium. For simplicity, let’s derive this fo
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