HCl is an acid or a base
Illustrate is HCl an acid or a base ?
Expert
Hydrochloric acid (HCl) as the name implies, is an acid. In fact, it is measured a strong acid because it separates completely in water to form Cl- and H3O+. Though, HCl can also act as a base in reactions with the acids stronger than it can as HClO4.
Briefly state the wavelengths which the human eye can see?
Common system According to this system, the individual members are named according to alkyl groups att
Choose the right answer from following. In a solution of 8.7g benzene C6H6 and 46.0 gm toluene ,(C6, H5, CH3) the mole fraction of benzene in this solution is: (a)1/6 (b)1/5 (c)1/2 (d)1/3
The boiling point of a solution of 0.11 gm of a substance in 15 gm of ether was found to be 0.1oC higher than that of the pure ether. The molecular weight of the substance will be (Kb = 2.16) (a) 148 &nbs
Elaborate a dipole moment?
Liquid solutions are obtained when the solvent is liquid. The solute can be a gas, liquid or a solid. In this section we will discuss the liquid solutions containing solid or liquid solutes. In such solutions the solute may or may not be volatile. We shall limit our d
Provide solution of this question. If 25 ml of 0.25 M NaCl solution is diluted with water to a volume of 500ml the new concentration of the solution is : (a) 0.167 M (b) 0.0125 M (c) 0.833 M (d) 0.0167 M
Silicon has three naturally occurring isotopes. 28Si, mass = 27.976927; 29Si, mass = 28.976495; 30Si, mass = 29.973770 and 3.10% abundance. What is the abundance of 28Si?
What is the percent error in calculating the density of water using the ideal gas law for the following conditions: a. 110 oC, 1 bar b. 210 oC 10 bar c. 374 o
Choose the right answer from following. Vapour pressure of a solution is: (a) Directly proportional to the mole fraction of the solvent (b) Inversely proportional to the mole fraction of the solute (c) Inversely proportional to the mole fraction of the solvent (d
18,76,764
1950533 Asked
3,689
Active Tutors
1429163
Questions Answered
Start Excelling in your courses, Ask an Expert and get answers for your homework and assignments!!