From where the tin is obtained
From where the tin is obtained? Briefly illustrate it.
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The tin is obtained in different places. Tin is mainly found in the ore cassiterite that is found in the Bolivia, Malaysia, Thailand and Nigeria.
Provide solution of this question. The weight of sodium carbonate required to prepare 500 ml of a seminormal solution is: (a) 13.25 g (b) 26.5 g (c) 53 g (d) 6.125 g
Which ion has the lowest radius from the following ions(a) Na+ (b) Mg2+ (c) Al3+ (d) Si4+ Answer: (d) All are the iso-electronic species but Si
When the catalyst exists in a different phase than that of reactants, it is said to be heterogeneous catalyst, and the catalysis is called heterogeneous catalysis. For example, SO2 can be oxidized to SO3
Colligative properties of a solution depends upon: (a) Nature of both solvent and solute (b) The relative number of solute and solvent particles (c) Nature of solute only (d) Nature of solvent only
Choose the right answer from following. What is the molarity of H2SO4 solution, that has a density 1.84 gm/cc at 35c and contains solute 98% by weight: (a) 4.18 M (b) 8.14 M (c)18.4 M (d)18 M
Transference numbers and molar conductors can be used to calculate ionic mobilities. This tables under is giving the transference numbers for positive ions at 25 degree C and the values obtained by extrapolation to infinite dilution: Q : Solution and colligative properties what is molarity of a solution of hcl which contains 49% by weight of solute and whose specific gravity is 1.41
what is molarity of a solution of hcl which contains 49% by weight of solute and whose specific gravity is 1.41
Select the right answer of the question. Molar solution contains: (a)1000g of solute (b)1000g of solvent (c)1 litre of solvent (d)1 litre of solution
Two tanks which contain water are connected to each other through a valve. The initial conditions are as shown (at equilibrium):
Help me to solve this problem. 4.0 gm of NaOH are contained in one decilitre of solution. Its molarity would be: (a) 4 M (b)2 M (c)1 M (d)1.5 M
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