From where the tin is obtained
From where the tin is obtained? Briefly illustrate it.
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The tin is obtained in different places. Tin is mainly found in the ore cassiterite that is found in the Bolivia, Malaysia, Thailand and Nigeria.
To 5.85gm of Nacl one kg of water is added to prepare of solution. What is the strength of Nacl in this solution (mol. wt. of nacl = 58.5)? (a) 0.1 Normal (b) 0.1 Molal (c) 0.1 Molar (d) 0.1 FormalAnswer:
What is main difference among anti-aromatic and the non-aromatic compounds?
Normal 0
Methane containing 4 mol% N2 is flowing through a pipeline at 105.1 kpa and 22 °C. To check this flow rate, N2 at the same temperature and pressure are introduced to the pipeline at the rate of 2.83 m3/min. At the end of the pipe (
The acid value definition is the number milligrams of KOH needed to neutralize the acid present in one gram oil and fats however why not employ NaOH for the neutralization?
Which one of the following non-ideal solutions shows the negative deviation: (a) CH3COCH3 + CS2 (b) C6H6 + CH3COCH3 (c) CCl4 + CHCl3
The Van't Hoff factor of the compound K3Fe(CN)6 is: (a) 1 (b) 2 (c) 3 (d) 4 Answer: (d) K3[Fe(CN)6] → 3K+
Transference numbers and molar conductors can be used to calculate ionic mobilities. This tables under is giving the transference numbers for positive ions at 25 degree C and the values obtained by extrapolation to infinite dilution: Q : Hybridization Atomic orbitals can be Atomic orbitals can be combined, in a process called hybridization, to describe the bonding in polyatomic molecules. Descriptions of the bonding in CH4 can be used to illustrate the valence bond procedure. We must arrive a
Atomic orbitals can be combined, in a process called hybridization, to describe the bonding in polyatomic molecules. Descriptions of the bonding in CH4 can be used to illustrate the valence bond procedure. We must arrive a
Hydrochloric acid solution A and B encompass concentration of 0.5N and 0.1N corresspondingly. The volumes of solutions A and B needed to make 2liters of 0.2N of HCL are: (i) 0.5l of A + 1.5l of B (ii) 1.5l of A + 0.5 l of B (iii) 1.0 l of A + 1.0l of B&nbs
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