--%>

Explain the process of adsorption of solids on gases.

The extent of adsorption of a gas on a solid adsorbent is affected by the following factors:

1. Nature of the gas

Since physical adsorption is non-specific in nature, every gas will get adsorbed on the surface of any solid to a lesser or greater extent. However, under given conditions of temperature and pressure, the easily liquefiable gases like NH3, HCl, CO2 etc. are adsorbed in a greater extent than the permanent gases such as H2, O2, N2 etc. it is because the van der Waal forces or molecular forces are more predominant in the former than in later category.

The ease with which a gas can be liquefied is mainly determined by its critical temperature Tc, Critical temperature of a gas is the temperature above which the gas cannot be liquefied irrespective of the pressure applied. A gas having higher critical temperature can be liquefied more easily and hence is adsorbed on the solid to greater and extent of adsorption for some gases.

We know that chemisorption is specific in nature. Therefore, in case of chemisorption a gas gets adsorbed on the solid only if it forms chemical bond with it.

2. Effect of nature of the adsorbent

The extent of adsorption of a gas also depends on the nature of adsorbent. Activated charcoal more easily adsorbs toxic gases like CH4, CO, etc. allows its frequent use in gas masks. Finely divided transition metals like Ni, CO, etc. adsorb permanent gases like H2N2O2, etc.

3. Specific area of the solid

Specific area of an adsorbing solid is the surface area available for adsorption per gram of the adsorbent. Greater the specific area of the solid, greater would be its adsorbent power. That is why porous or finely divided forms of adsorbents adsorb more extensively. However, the pores should be large enough to allow the gas molecules to allow the gas molecules to enter them.

4. Effect of pressure of the gas

In order to understood the effect of pressure on the adsorption of a gas on some solid, we must keep in mind that adsorption is a reversible process and is accompanied by decrease in pressure. Therefore, it is expected that a given temperature, the extent of the adsorption increases with the increase in pressure. The extent of the adsorption is generally expressed as x/m where m is the mass of the adsorbent and x is that of the adsorbate when equilibrium has been attained. A graph drawn between extent of adsorption (x/m) and the pressure p of the gas at constant temperature is called adsorption isotherm. Adsorption isotherms of different shapes have been observed experimentally. Two most common types of adsorption isotherms are Freundlich adsorption isotherms and Langmuir adsorption isotherm.

5. Effect of temperature

As already discussed the adsorption at a surface initially increases till a saturation point is achieved. At this juncture an equilibrium is established as represented below.
                                         
Adsorption  727_Physical adsorption.png  Desorption; Δ H = +ve

As adsorption is accompanied by evolution of heat, so in accordance with Le-Chatelier's principle, the magnitude of adsorption should decrease with rise in temperature and this is actually so.

A graph drawn between extent of adsorption (x/m) and temperature (t) at constant pressure is called adsorption isobar. 

6. Activation of adsorbent

Activation of an adsorbent means increasing the adsorbing power of the adsorbent. This can be done in various different ways. One possible way of doing it is to increase the specific area of the adsorbent. This can be done either by making the surface of adsorbent or by breaking it into small pieces. However, if the particles are made very small, then the interparticle spaces will be too small to allow the penetration of gas molecules and hence, the extent of adsorption may increase by certain specific treatments. For example, wood charcoal can be activated by heating it between 650 K and 1330 K in vacuum, air or super-heated steam.

   Related Questions in Chemistry

  • Q : Molar concentration of Iron chloride

    Provide solution of this question. A certain aqueous solution of FeCl3 (formula mass =162) has a density of 1.1g/ml and contains 20.0% Fecl. Molar concentration of this solution is: (a) .028 (b) 0.163 (c) 1.27 (d) 1.47

  • Q : Problem on Adiabatic expansion

    Calculate the change in entropy for the system for each of the following cases. Explain the sign that you obtain by a physical argument a) A gas undergoes a reversible, adiabatic expansion from an initial state at 500 K, 1 MPa, and

  • Q : Problem on colligative properties

    Choose the right answer from following. The magnitude of colligative properties in all colloidal dispersions is : (a) Lowerthan solution (b)Higher than solution(c) Both (d) None

  • Q : Molecular basis of third law. The

    The molecular, or statistical, basis of the third law can be seen by investigating S = k in W.The molecular deductions of the preceding sections have led to the same conclusions as that stated in the third law of thermodynamics, namely, that a value can be

  • Q : Law of multiple proportions and Law of

    Describe the difference between law of multiple proportions and law of definite proportions?

  • Q : Direction of dipole moment expected

    Illustrate the direction of the dipole moment expected for hydrogen bromide?

  • Q : Theory of three dimensional motion

    Partition function; that the translational energy of 1 mol of molecules is 3/2 RT will come as no surprise. But the calculation of this result further illustrates the use of quantized states and the partition function to obtain macroscopic properties. The partition fu

  • Q : What is covalent radii? Explain its

    Average covalent radii can be assigned on the basis of molecular structures. The accumulation of structural data by spectroscopic studies and both electron and x-ray diffraction studies allows one to investigate the possibili

  • Q : Problem related to molality Help me to

    Help me to solve this problem. What is the molality of a solution which contains 18 g of glucose (C6,H12, O6) in 250 g of water:  (a) 4.0 m (b) 0.4 m (c) 4.2 m (d) 0.8 m

  • Q : Latent heat of vaporization Normal

    Normal butane (C4H10) is stored as a compressed liquid at 90°C and 1400 kPa. In order to use the butane in a low-pressure gas-phase process, it is throttled to 150 kPa and passed through a vaporizer. The butane emerges from the vaporizer as a